replacing close with an array [SOLVED]

Guest · Mar 23 2007

I have built an array with a series of numbers. I'd like to take a moving average of these numbers without having to do it manually (ex (array[0]+array[1]+.....+array[100])/100). Is there anyway I can take this same calculation using the built in function? (ex replace close with the array, xaverage(array[0])) Is this possible?

Stanley Miller · Mar 27 2007

You can use array_sum function i.e.:

Code: Select all


var avg(0):

avg = array_sum(array, 0, 100) / 101

Guest · Mar 27 2007

that will work, I tried the following, however, it's showing an error

Array: TradingDataArray[159,4]

value9 = array_sum(TradingDataArray[159,0],111,159)

Stanley Miller · Mar 27 2007

Code: Select all


Arrays: TradingDataArray[](0);

value9 = array_sum(TradingDataArray,111,159);